Quote:
On 2003-01-31 17:00, Rupert The Guerilla Rat wrote:
Death from above damage = attacking mech weight / 10 x 3, rounding up.
Christ, how I remembered that after 4 years of not playing Battletech is beyond me.
If it makes you feel any better, I haven't played BT in more than five years, and I hadn't played for much more than a few months back then either. And yet, I remember the following:
I once designed a mech for the express purpose of Death From Above. It was a
100 ton quad mech (piloting bonus, cause the extra legs give stability at the expense of places to put weapons) with jump jets, maxed leg armor (cause the DFA damage hits your legs too), biggest engine mountable (as your land speed for some inexplicable reason limits your speed when you're flying using the rockets in your feet), and two LB-X 20 Autocannons with scatter-rounds.
The rationale being that an enemy mech's head can't possibly sustain more than 12 damage. The DFA damage (30, as per the formula) gets divided into six five-point chunks, each of which has a 1/6 chance of hitting the enemy's head. If you can do 2 damage to the head with the autocannons the round before (not THAT hard since each of the 20 rounds targets separately, though THAT's going to make rolling hit locations for however many of the 20 hit a real joy) and then get 2 sixes in 6 D6 (or 3 6's in 6D6 without the softening up damage), then, as they say in Camp McLeod, THERE CAN BE ONLY ONE! *g*
[edit - Know your Scottish clan spellings. lol]
<font size=-1>[ This Message was edited by: GreenArmadillo on 2003-01-31 19:34 ]</font>